Asked by Jake
A motorcyclist who is moving along an x-axis has an acceleration given by a=(6.47-2.15t) for 0 >= t <= 6.0 s, where a is in m/s2 and t is in seconds. At t = 0, the velocity and position of the cyclist are 3.20 m/s and 7.30 m. For the time interval from 0 >= t <= 6.0 s, what is the difference between the maximum speed and the average speed of the motorcyclist?
Taking the integral of acceleration I got
v= -1.145t^2 + 6.60t +3.20
x= -.5725t^3 +3.3t^2 +3.20t + 7.30 (position function)
Not sure what to do from here.
Taking the integral of acceleration I got
v= -1.145t^2 + 6.60t +3.20
x= -.5725t^3 +3.3t^2 +3.20t + 7.30 (position function)
Not sure what to do from here.
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