Asked by Janice
Form a third degree polynomial function with real coefficients such that 2+i and -5 are zeros.
f(x)= ?
f(x)= ?
Answers
Answered by
Steve
since we want real coefficients, complex roots must come in conjugate pairs. So,
f(x) = (x+5)(x-(2+i))(x-(2-i))
= x^3 + x^2 - 15x + 25
f(x) = (x+5)(x-(2+i))(x-(2-i))
= x^3 + x^2 - 15x + 25
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