Asked by Roxane

The total seating capacity of an auditorium is 1,065. The first row has 21 seats arithmetic series and each row has one seat more than the row in front of it. How many rows of seats are there in the auditorium?

Answers

Answered by Reiny
In your arithmetic series:
a = 21
d = 1
n = ??
sum(n) = 1065

1065 = (n/2)(2(21) + (n-1)(1) )
2130 = n(42 + n - 1)
2130 = n^2 + 41n
n^2 + 41n - 2130 = 0
(n-30)(n + 71) = 0

n = 30 or n = -71 , but n > 0

there are 30 rows
Answered by Yawa mo
Bubu kayu
Answered by chad
What formula did you use? What is it called?
Answered by Litsi
Way pulos
Answered by 30 rows
I learned na bogo jud kog math
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