Question
A 2.0 kg block of iron slides along a floor, decreasing its speed from 4.0 m/s to 1.0 m/s.
a) How much work does the frictional resistance of the floor do on the block?
b) If the reduction in velocity occurred over a distance of 10 m, what was the force of
friction acting on the block?
c) What impulse was delivered to the block?
a) How much work does the frictional resistance of the floor do on the block?
b) If the reduction in velocity occurred over a distance of 10 m, what was the force of
friction acting on the block?
c) What impulse was delivered to the block?
Answers
Damon
work = change in Ke
= (1/2)(2)(1^2-4^2) = -15 J
negative because energy taken out not put in
work = force * distance in direction of force
-15 = F (10)
F = -1.5 N
impulse = change in momentum
I = 2 ( 1 - 4) = -6 kg m/s
= (1/2)(2)(1^2-4^2) = -15 J
negative because energy taken out not put in
work = force * distance in direction of force
-15 = F (10)
F = -1.5 N
impulse = change in momentum
I = 2 ( 1 - 4) = -6 kg m/s
idnchfywek
THANKS