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Farmer Ed has 9 comma 0009,000 meters of fencing, and wants to enclose a rectangular plot that borders on a river. If Farmer E...Asked by Janice
Farmer Ed has
9,000 meters of fencing, and wants to enclose a rectangular plot that borders on a river. If Farmer Ed does not fence the side along the river, what is the largest area that can be enclosed?
9,000 meters of fencing, and wants to enclose a rectangular plot that borders on a river. If Farmer Ed does not fence the side along the river, what is the largest area that can be enclosed?
Answers
Answered by
Damon
x = length
y = width
x + 2 y = 9000 or x = 9000 - 2 y
A = x y
so
A = (9000-2y)y
2 y^2 - 9000 y = - A
y^2 - 4500 y = -A/2
y^2 - 4500 y +(4500/2)^2 = -A/2 + 5,062,500
(y-2250)^2 = -(1/2)(A-10,125,000)
so
width = 2250
length = 4500
area = 10,125,000 m^2
y = width
x + 2 y = 9000 or x = 9000 - 2 y
A = x y
so
A = (9000-2y)y
2 y^2 - 9000 y = - A
y^2 - 4500 y = -A/2
y^2 - 4500 y +(4500/2)^2 = -A/2 + 5,062,500
(y-2250)^2 = -(1/2)(A-10,125,000)
so
width = 2250
length = 4500
area = 10,125,000 m^2
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