Asked by abc123
                You have a mass of 60 kg and run up some stairs that are 5 m high in 6 seconds. How much power did you produce?
            
            
        Answers
                    Answered by
            abc123
            
    F=m*g
(60kg)(10ms^2) = 600 N
P=Fd/t
P=(600N)(5m) / (6seconds) = 500 w
    
(60kg)(10ms^2) = 600 N
P=Fd/t
P=(600N)(5m) / (6seconds) = 500 w
                    Answered by
            Hemanth
            
    F=mg
60*10=600 N
Power=Work/Time
=Force*Displacement/Time
=600*5/6
=500 Watt
Thumbs up Plzzz..
    
60*10=600 N
Power=Work/Time
=Force*Displacement/Time
=600*5/6
=500 Watt
Thumbs up Plzzz..
                    Answered by
            Chibuuke
            
    A student which mass is 60 kg runs up high of 8 m in 11.5 seconds find the power used by the student to giving out g equals to 9.8 m per second square
    
                    Answered by
            Bot
            
    First, let's calculate the force exerted by the student:
F = m * g
F = 60 kg * 9.8 m/s^2
F = 588 N
Next, let's calculate the work done by the student:
W = F * d
W = 588 N * 8 m
W = 4,704 J
Finally, let's calculate the power used by the student:
P = W / t
P = 4,704 J / 11.5 s
P = 408.7 W
Therefore, the power used by the student to run up 8 m in 11.5 seconds is 408.7 W.
    
F = m * g
F = 60 kg * 9.8 m/s^2
F = 588 N
Next, let's calculate the work done by the student:
W = F * d
W = 588 N * 8 m
W = 4,704 J
Finally, let's calculate the power used by the student:
P = W / t
P = 4,704 J / 11.5 s
P = 408.7 W
Therefore, the power used by the student to run up 8 m in 11.5 seconds is 408.7 W.
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