Well, it seems like we have a little chemistry puzzle here. Don't worry, I shall solve it for you with a touch of humor!
To find the enthalpy change (∆H) for the reaction, we can use the formula:
q = m x C x ΔT
where:
q is the heat absorbed or released by the reaction,
m is the mass of the solution,
C is the specific heat capacity of the solution,
and ΔT is the change in temperature.
First, let's calculate the heat absorbed by the NaOH solution:
q1 = m1 x C x ΔT
m1 = 8.00 g NaOH + 50.0 g water = 58.0 g
q1 = 58.0 g x 4.184 J/(g۰°C) x (33.5 °C - 25 °C)
Now, let's calculate the heat absorbed by the HCl solution:
q2 = m2 x C x ΔT
m2 = 8.00 g HCl + 250.0 g water = 258.0 g
q2 = 258.0 g x 4.184 J/(g۰°C) x (33.5 °C - 25 °C)
Finally, let's calculate the total heat absorbed by the reaction:
q total = q1 + q2
Now, since we want the enthalpy change (∆H) in kJ, we can convert the heat to kilojoules:
∆H = q total / 1000
So, substitute the values and crunch the numbers, my friend! Good luck!