A 30-kg girl is bouncing on a trampoline. During a certain interval after she leaves the surface of the trampoline, her kinetic energy decreases to 205 J from 435 J. How high does she rise during this interval? Neglect air resistance.

asked by Lola

9 years ago

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1 answer

m g h = (435-205)

h = (435-25)/( 30*9.81)

answered by Damon

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Question

A 30-kg girl is bouncing on a trampoline. During a certain interval after she leaves the surface of the trampoline, her kinetic energy decreases to 205 J from 435 J. How high does she rise during this interval? Neglect air resistance.

1 answer

m g h = (435-205)

h = (435-25)/( 30*9.81)

Damon · Accepted Answer

m g h = (435-205) h = (435-25)/( 30*9.81)