Asked by Patricia
Gateway Arch in St. Louis was constructed using the equation
y=211.49-20.96cosh(0.03291765x)
where |x|<=91.20
a) what is the height at its center in meters
b) At what points is height 70m (2 values of x)
c) what is the slope of arch at points in part b
y=211.49-20.96cosh(0.03291765x)
where |x|<=91.20
a) what is the height at its center in meters
b) At what points is height 70m (2 values of x)
c) what is the slope of arch at points in part b
Answers
Answered by
Steve
a) well, cosh(0) = 1
b)
211.49-20.96cosh(0.03291765x) = 70
20.96cosh(0.03291765x) = 141.49
cosh(0.03291765x) = 6.75
x = arccosh(6.75)/0.03291765
c)
y' = -(20.96)(0.03291765x)sinh(0.03291765x)
so, just plug in the values from (b).
Use the graphs's symmetry to eliminate one calculation.
b)
211.49-20.96cosh(0.03291765x) = 70
20.96cosh(0.03291765x) = 141.49
cosh(0.03291765x) = 6.75
x = arccosh(6.75)/0.03291765
c)
y' = -(20.96)(0.03291765x)sinh(0.03291765x)
so, just plug in the values from (b).
Use the graphs's symmetry to eliminate one calculation.
Answered by
Anonymous
465
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