Asked by Patricia

Gateway Arch in St. Louis was constructed using the equation
y=211.49-20.96cosh(0.03291765x)
where |x|<=91.20
a) what is the height at its center in meters
b) At what points is height 70m (2 values of x)
c) what is the slope of arch at points in part b

Answers

Answered by Steve
a) well, cosh(0) = 1
b)
211.49-20.96cosh(0.03291765x) = 70
20.96cosh(0.03291765x) = 141.49
cosh(0.03291765x) = 6.75
x = arccosh(6.75)/0.03291765
c)
y' = -(20.96)(0.03291765x)sinh(0.03291765x)
so, just plug in the values from (b).
Use the graphs's symmetry to eliminate one calculation.
Answered by Anonymous
465
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions