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a policeman is pursuing a snatcher who is ahead by 72 of his own leaps. the snatcher takes 6 leaps while the cop takes 5 leaps,...Asked by megan
a policeman is pursuing a snatcher who is ahead by 72 of his own leaps. the snatcher takes 6 leaps while the cop takes 5 leaps, but 4 leaps of the snatcher are as long as 3 leaps of the cop. how many leaps will the cop make before he catches the snatcher?
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Answered by
Steve
Let's say the cop's leaps are 4 ft, while the snatcher's are 3 feet,
and the cop's leaps take 6 seconds, while the snatcher's take 5 seconds.
So, after x seconds, the distances and times must match up:
(x/6)(4) = (x/5)(3) + 72*3
x = 3240
So, it will take 3240/6 = 540 cop leaps to ctahc up.
and the cop's leaps take 6 seconds, while the snatcher's take 5 seconds.
So, after x seconds, the distances and times must match up:
(x/6)(4) = (x/5)(3) + 72*3
x = 3240
So, it will take 3240/6 = 540 cop leaps to ctahc up.
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