Question

Let f(x)=(x-3)^2(x - 9).
The y-intercept is y= ?-81 or -15

The x-intercepts are x= ?0,3

The end behavior on the right is ?even so + (enter "+" for rises, "-" for falls)

The end behavior on the left is ?positive so + (enter "+" for rises, "-" for falls)
I came up with a few different answers and not sure where going wrong.

Answer 1

The y axis intercept is when x = 0
Here when x = 0
y = (-3)^2(-9) = 9 * -9 = -81

The x intercepts are when y = 0
which is when x = 3 (just barely hits the axis) and when x = 9

On the right is when x is very large positive.
That is y ---> x^2 (x) = x^3 rising

on the left x is big negative
y ---> |x|^2 (x) so big negative getting bigger negative