Asked by nicole
How many terms are there In an arithmetic Sequence with a common different of 4 and with the first and last term 3 and 59 Respectively.
Answers
Answered by
Sheena
Let Common difference = d =4
First term= a -3
Last term = l = 59
And number of terms = n
l=a+(n-1)d
59= 3 + (n-1)4
59=3+4n-4
59=4n-1
60=4n
60/4 =n
15=n
#There are 15 terms in the sequence
First term= a -3
Last term = l = 59
And number of terms = n
l=a+(n-1)d
59= 3 + (n-1)4
59=3+4n-4
59=4n-1
60=4n
60/4 =n
15=n
#There are 15 terms in the sequence
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