Question

can someone elxplai to me how to solve this differential equation.

dy/dx= (x^2+3y^2)/2xy

Answer 1

be careful with parentheses
like use
dy/dx= (x^2+3y^2)/ ( 2xy )

http://www.wolframalpha.com/widgets/view.jsp?id=e602dcdecb1843943960b5197efd3f2a

y = +/- x (cx-1)^.5

Answer 2

Note Mathmate response to the question below titled
Calculus AB