Asked by Samantha
Ksp fo CaSO4 is 6.1*10?-5. how many grams of CaCl2 must be added to 500ml of 0.010M H2SO4 to just start preciptation of CaSO4?
I cant figure this out at all.
I cant figure this out at all.
Answers
Answered by
DrBob222
I would do this.
For a ppt to form you know Ksp must be exceeded; therefore,
..........CaSO4(s) ==> Ca^2+ + SO4^2-
E.........solid........x........x
You also know that adding 0.01M H2SO4 will increase the solubility of CaSO4 due to the reaction of SO4^2- + H^+ ==> HSO4^-.
You work this the same was as you did the CaCO3 problem.
solubility CaSO4 = (Ca^+) = S
S = SO4^2- + HSO4^-
For HSO4^-, use k2 and solve for (HSO4^-) = some number x SO4^2-.
Plug into S = SO4 + HSO4 which makes
S = some number x SO4
Then SO4 = S/some number and that goes into the Ksp expression. Solve for S = Ca^2+ which gives M (mols/L), take half to convert to 500 mL, and convert to grams CaCl2.
For a ppt to form you know Ksp must be exceeded; therefore,
..........CaSO4(s) ==> Ca^2+ + SO4^2-
E.........solid........x........x
You also know that adding 0.01M H2SO4 will increase the solubility of CaSO4 due to the reaction of SO4^2- + H^+ ==> HSO4^-.
You work this the same was as you did the CaCO3 problem.
solubility CaSO4 = (Ca^+) = S
S = SO4^2- + HSO4^-
For HSO4^-, use k2 and solve for (HSO4^-) = some number x SO4^2-.
Plug into S = SO4 + HSO4 which makes
S = some number x SO4
Then SO4 = S/some number and that goes into the Ksp expression. Solve for S = Ca^2+ which gives M (mols/L), take half to convert to 500 mL, and convert to grams CaCl2.
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