Asked by walter

A 12.6 mL sample of vinegar, containing acetic acid, was titrated using 0.542 M NaOH solution. The titration required 24.1 mL of the base. what is the molar concentration of acid in the vinegar?'
Answered by bobpursley
both are monoprotic...

Ma*Va=Mb*Vb
Ma=Mb* Vb/va=.542*24.1/12.6=
Answered by DrBob222
You must know that 1 mol acetic acid = 1 mol NaOH
mols NaOH - M x L = ?
mols acetic acid = the same

M acid = mols acid/L acid. Substitute and solve for M acid.
Answered by DrBob222
This line
mols NaOH - M x L = ?
should read
mols NaOH = M x L = ?
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