A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.24 m/s. The car is a distance d away. The bear is 31.1 m behind the tourist and running at 4.50 m/s. The tourist reaches the car safely. What is the maximum possible value for d?

Answer 1

This is not Physics.

tourist runs distance d
bear runs distance (d+31.1)
same time t

d = 3.24 t
d+31.1 = 4.5 t
so
d + 31.1 = 4.5(d/3.24)

3.24 d + 100.7 = 4.5 d

d = 80 meters max
this tourist is no track star :(