Also my other question asked to perform the indicated operation AND STATE THE DOMAIN.
(5x+7)*(x-9) = 5x^2 -38x-63 < ANSWER
How would I write my Domain?
Identify the x-intercepts, local maximum, and local minimum of the graph of
f(x)=x^3+2x^2-13x+10
I am confused on where to begin.
6 answers
I also wasn't sure how to put the equation together..
perform the indicated operation...
g(f(x)); f(x)=x^2+3x; g(x)=2x+1
perform the indicated operation...
g(f(x)); f(x)=x^2+3x; g(x)=2x+1
-5, 1 , 2
http://www.wolframalpha.com/widgets/view.jsp?id=a7d8ae4569120b5bec12e7b6e9648b86
(right away you should see that one works, then you have a quadratic)
domain of parabola is all real x. (range is another story)
g = (2x+1)^2 + 3(2x+1)
now you multiply out and collect like terms
http://www.wolframalpha.com/widgets/view.jsp?id=a7d8ae4569120b5bec12e7b6e9648b86
(right away you should see that one works, then you have a quadratic)
domain of parabola is all real x. (range is another story)
g = (2x+1)^2 + 3(2x+1)
now you multiply out and collect like terms
On the first one, it's easy enough to find the intercepts. Coming up with the max and min is a bit tricker, if you don't have calculus as a tool.
x = -b/2a which gives you a turning point which will help you come up with the max or the min.
Once you fine x, then you can find y by substituting back into the original equation.
Range can also be found by using this turning point.
Once you fine x, then you can find y by substituting back into the original equation.
Range can also be found by using this turning point.
x = -b/2a only works with quadratic functions. When the polynomial is of degree 3 or higher, all bets are off.
In this case, there is a local max or min when 3x^2+4x-13=0
In this case, there is a local max or min when 3x^2+4x-13=0
3 answers