Assuming you meant
(√3+√2)/(3-√2)
multiply top and bottom by 3+√2 and you have
(√3+√2)(3+√2)/7
= (3√3+√6+3√2+2)/7
I suspect a typo. Maybe you can repost with standard characters.
(¡Ì3+¡Ì2) (3-¡Ì2)
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