Asked by James

A box slides along a rough floor with initial kinetic energy of 7 J. A person pushes on the box, in the same direction as its velocity doing 25 J of work. The velocity of the box is doubled. Find the magnitude of the work done by friction.
Answered by bobpursley
initial KE=7
final KE=7+25-frictionwork
velocity is doubled, so KE is quadrupled.
final KE=28J

28=7+25-friction
solve for friction
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