Asked by kim


The equation of the line that goes through the point ( 2, 5 ) and is parallel to the line going through the points ( -2 ,4 ) and ( 6 ,2 ) can be written in slope-intercept form y = mx+b with:
m =

b =
Answered by Steve
the slope is (2-4)/(6+2) = -1/4

So, in point-slope form, you have

y-5 = -1/4 (x-2)

Now massage that into slope-intercept form.
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