Asked by kim

An equation of a line through (-3, -6) which is perpendicular to the line y=-5 x +3 has slope: I know the slope is 1/5 having problem with y-intercept is

Answers

Answered by bobpursley
y intercept is when x is zero.

y=mx+b
-6=1/5 *-3 + b
solve for b.
Answered by Steve
or, just use the point-slope form of the line. You know the slope is 1/5 and it goes through (-3,-6). So,

y+6 = 1/5 (x+3)

You can massage that as you will.
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