How would you solve:

5 cos x + 2 = 0
In the domain of 0 degrees to 360 degrees

3 answers

5 cos x + 2 = 0
5 cos x = -2
cos x= -2/5
arccos (-2/5) = answer (check to see if you are supposed to answer in degrees or radians - change calculator settings accordingly)
also recall that cos(x) is negative in QII and QIII
Cos x = -0.40
X = 113.6o