Asked by Anonymous
Suppose that weights for women in their 20’s average 125 lb., with a standard deviation of 14 lb. For a sample of size 50 how likely is it that a random sample will produce a mean weight between 100 and 140 lb.?
Answers
Answered by
PsyDAG
Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability between the two Z scores.
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability between the two Z scores.
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