Asked by LittlePanda
A rectangle is bounded by the x axis and the semicircle = square root 25-x^2. What length and width should the rectangle have so that its area is a maximum?
When I worked the problem out(which is a bit detailed). I started with y = square root 25-x^2 then A = 2x square root 25-x^2. For my answer, I got y = square root 25-25/2 = square root 25/2= 5 square root 2/2. Then A= 5 square root 2 times 5 square root 2/2 =25. But I don't know if my answer 25 is correct.
When I worked the problem out(which is a bit detailed). I started with y = square root 25-x^2 then A = 2x square root 25-x^2. For my answer, I got y = square root 25-25/2 = square root 25/2= 5 square root 2/2. Then A= 5 square root 2 times 5 square root 2/2 =25. But I don't know if my answer 25 is correct.
Answers
Answered by
Bosnian
Copy your question in google.
When you see list of results click on :
e n . a l l e x p e r t s . c o m
You will see answer.
When you see list of results click on :
e n . a l l e x p e r t s . c o m
You will see answer.
Answered by
LittlePanda
Okay thanks :), that did help
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