Asked by Uroosa

A bag contains 3 apples and 2 oranges. Another bag contains 2 apples and 4 oranges . A bag and a fruit are picked at random. The probability that the fruit will be apple is
Answered by Steve
(1/2)(3/5) + (1/2)(2/6)
Answered by Anonymous
A bag contains 3 apples and 2 oranges. Another bag contains 2 apples and 4 oranges . A bag and a fruit are picked at random. The probability that the fruit will be apple is
Answered by Ack
Orange and apple juice
Answered by Trinitee
3/2 +2/4 = 5/4
Answered by an oofer
steve said (1/2)(3/5) + (1/2)(2/6)
You can get 3/10+ 1/6 =9/30+5/30=14/30=7/15
Answered by M
Bag 1 has five fruits in total, three being an apple and two being an orange. If this bag is picked, the chance the fruit would be an apple would be 3/5, or 60% of the time.

Bag 2 has six fruits in total, two being an apple and four being an orange. If this bag is picked, the chance the fruit would be an apple would be 2/6, or 33.333...% of the time.

You have a 100% chance of picking either bag, so just think of this as the fruits being in the same bag. There would be 3+2 apples in total, and 2+4 oranges in total. All together, there are 11 fruits. 5 of these fruits are apples.

So, the chance of picking an apple is 5/11, or a 45.454545...% chance of picking an apple. This means, on average, if you have 100 random fruits with the same probability of being in the bag as is displayed previously in the problem, you will choose an apple 45 times and an orange 55 times.
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