Asked by Anonymous
Use sine law to explain why the 2 equal sides of an isoceles triangle must be opposite the two equal angles
Answers
Answered by
Steve
if sides a and b are equal, then
a/sinA = b/sinB
means that
a/sinA = a/sinB
so sinA = sinB
Now, A and B need not be equal if their sines are equal, but in that case A = 180°-B and your triangle is just a flat line.
a/sinA = b/sinB
means that
a/sinA = a/sinB
so sinA = sinB
Now, A and B need not be equal if their sines are equal, but in that case A = 180°-B and your triangle is just a flat line.
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