Asked by Summer.
Find the equations of lines parallel to and perpendicular to the line 3x - 2y = -1 and passing through the point (3, -2)
Answers
Answered by
Cosine
Rearranging,2y=3x+1 so m=3/2 since the line is parallel to the equation,it gradient is 3/2.so it equation is:y-(-2)=3/2(x-3) 2y+4=3x-9 2y=3x-13 if it is perpendicular,it gradient is -1/3/2=-2/3 so the equation:y-(-2)=-2/3(x-3) 3y+6=-2x+6 3y=-2x
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.