Question

Find the equations of lines parallel to and perpendicular to the line 3x - 2y = -1 and passing through the point (3, -2)
Cosine
Rearranging,2y=3x+1 so m=3/2 since the line is parallel to the equation,it gradient is 3/2.so it equation is:y-(-2)=3/2(x-3) 2y+4=3x-9 2y=3x-13 if it is perpendicular,it gradient is -1/3/2=-2/3 so the equation:y-(-2)=-2/3(x-3) 3y+6=-2x+6 3y=-2x