Asked by Anonymous
Simplify the trigonometric function
sin^4x-cos^4x
cos^2â-sin^2â=1+2cosâ
(1+cot^2x )(cos^2x )=cot^2x
cot^2t/csct =(1-sin^2t)/sint (Work on both sides!)
sinècscè- sin^2è=cos^2è
sin^4x-cos^4x
cos^2â-sin^2â=1+2cosâ
(1+cot^2x )(cos^2x )=cot^2x
cot^2t/csct =(1-sin^2t)/sint (Work on both sides!)
sinècscè- sin^2è=cos^2è
Answers
Answered by
Damon
sin^4x-cos^4x = (sin^2 x+cos^2 x)(sin^2 x -cos^2 x
= 1 (sin^2 x - cos^2 x)
= 2 sin^2 x - 1
= 1 (sin^2 x - cos^2 x)
= 2 sin^2 x - 1
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