Asked by kem

3x^2 kx-k=3x prove that this equation has rational roots for all ration values of K thanks
Answered by Steve
You are missing a + or - sign in there.
Answered by kem
Its 3x^2 kx-k=3x prove that this equation has rational roots for all rational values of K.
Answered by Steve
Sorry.

3x^2 kx-k

makes no sense. Is it

3x^2+kx-k
or
3x^2-kx-k

?

As it stands, since <u>a b</u> means a*b, you have

3x^2*kx-k = 3k
3kx^3-k = 3x
3kx^3-3x-k = 0

which clearly does not work.
Answered by kem
3x^2 kx-k=3x
Answered by kem
It's 3x^2+kx-k=3k
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