Asked by Arielle

how many grams of butane must be burned in an excess of o2 gas in order to produce 7.64l of co2?

Answers

Answered by DrBob222
At what conditions? The volume of CO2 varies with both T and P. I'll assume STP.

2C4H10 + 13O2 ==> 8CO2 + 10H2O

mols CO2 = 7.64/22.4 = ?
Using the coefficients in the balanced equation, convert mols CO2 to mols C4H10.
Then convert mols C4H10 to grams. g = mols C4H10 x molar mass C4H10.
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