A 1.00 kg piece of aluminum metal at 80 degrees Celsius is placed in water that is 25 degrees Celsius. How much water is needed to cool the aluminum to 65 degrees?

Question

I'm stuck as where to start with this.

Answer 1

heat lost by Al + heat gained by H2O = 0

[mass Al x specific heat Al x (Tfinal-Tinital)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0

Substitute and solve for mass H2O.