Asked by Makaila
For each quadratic function, find the axis of symmetry of its graph.
y=3x^2-6x+4
y=3x^2-6x+4
Answers
Answered by
Reiny
complete the square ....
y = 3(x^2 - 6x ....) + 4
= 3(x^2 - 6x + 9 - 9) + 4
= 3( (x-3)^2 - 9) + 4
= 3(x-3)^2 - 27 + 4
= 3(x-3)^2 - 23
I trust you can take it from here.
y = 3(x^2 - 6x ....) + 4
= 3(x^2 - 6x + 9 - 9) + 4
= 3( (x-3)^2 - 9) + 4
= 3(x-3)^2 - 27 + 4
= 3(x-3)^2 - 23
I trust you can take it from here.
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