Asked by Mark

If the distance between (b, 3) and (7, 3) is 3.5 units, find all possible values of b.

Answers

Answered by Jai
Use the distance formula:
d^2 = (y2 - y1)^2 + (x2 - x1)^2
where
d = distance
(x1, y1) and (x2, y2) = points

Thus,
3.5^2 = (3 - 3)^2 + (7 - b)^2
12.25 = 0 + 49 - 14b + b^2

Now solve for b.
Answered by Steve
Or, you can stop at:

3.5^2 = (3 - 3)^2 + (7 - b)^2

and you have

(b-7)^2 = 3.5^2
b-7 = ±3.5
b = 7±3.5
Answered by Reiny
or, you can notice that they lie on the same horizontal line, so (b,3) is either 3.5 units to the right or to the left of (7,3)
so b = 7 ± 3.5

which is what Steve shows in his last line as well.
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