Asked by Mark
If the distance between (b, 3) and (7, 3) is 3.5 units, find all possible values of b.
Answers
Answered by
Jai
Use the distance formula:
d^2 = (y2 - y1)^2 + (x2 - x1)^2
where
d = distance
(x1, y1) and (x2, y2) = points
Thus,
3.5^2 = (3 - 3)^2 + (7 - b)^2
12.25 = 0 + 49 - 14b + b^2
Now solve for b.
d^2 = (y2 - y1)^2 + (x2 - x1)^2
where
d = distance
(x1, y1) and (x2, y2) = points
Thus,
3.5^2 = (3 - 3)^2 + (7 - b)^2
12.25 = 0 + 49 - 14b + b^2
Now solve for b.
Answered by
Steve
Or, you can stop at:
3.5^2 = (3 - 3)^2 + (7 - b)^2
and you have
(b-7)^2 = 3.5^2
b-7 = ±3.5
b = 7±3.5
3.5^2 = (3 - 3)^2 + (7 - b)^2
and you have
(b-7)^2 = 3.5^2
b-7 = ±3.5
b = 7±3.5
Answered by
Reiny
or, you can notice that they lie on the same horizontal line, so (b,3) is either 3.5 units to the right or to the left of (7,3)
so b = 7 ± 3.5
which is what Steve shows in his last line as well.
so b = 7 ± 3.5
which is what Steve shows in his last line as well.
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