Asked by Gaby
The image of an eraser in a magnifying glass is three times the eraser’s actual size and has a width of 14.4 cm. What is the actual width of the eraser in cm?
a) 14.4 cm.
b) 3 cm.
c) 43.2 cm.
d) 4.8 cm.
is it C?
A square has 16-cm sides. What is the perimeter of the image of this square after a dilation of 0.8?
a) 12.8 cm.
b) 51.2 cm.
c) 20 cm.
d) 80 cm.
is it A?
A dilation maps triangle LMN to triangle L’M’N’. MN = 14 in. and M’N’ = 9.8 in. If LN = 13 in., what is L’N’?
a) 18.6 in.
b) 9.1 in.
c) 9.8 in.
d) 0.7 in.
is it B?
a) 14.4 cm.
b) 3 cm.
c) 43.2 cm.
d) 4.8 cm.
is it C?
A square has 16-cm sides. What is the perimeter of the image of this square after a dilation of 0.8?
a) 12.8 cm.
b) 51.2 cm.
c) 20 cm.
d) 80 cm.
is it A?
A dilation maps triangle LMN to triangle L’M’N’. MN = 14 in. and M’N’ = 9.8 in. If LN = 13 in., what is L’N’?
a) 18.6 in.
b) 9.1 in.
c) 9.8 in.
d) 0.7 in.
is it B?
Answers
Answered by
Steve
since the image is 3 times the actual size, you want 14.4/3 = 4.8 for the actual size
The other two are correct.
The other two are correct.
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