Asked by rhidicde

Kristen lives directly east of the park. The football field is directly south of the park. The library sits on the line formed between Kristen’s home and the football field at the exact point where an altitude to the right triangle formed by her home, the park, and the football field could be drawn. The library is 6 miles from her home. The football field is 8 miles from the library.

How far is the library from the park? How far is the park from the football field?
√22 miles; 2√10 miles
2√10 miles; √22 miles
6√2 miles; 6√11 miles
6√11 miles; 6√2 miles
Answered by rhidicde
I think it's C, but I'm not sure. Is that correct?
Answered by Steve
How far is the library from the park?
x^2 = 6*8

I don't see that as a choice.

??
Answered by rhidicde
hmmm... I'm a bit confused. could you help me out with just how to set the equation up?
Answered by Steve
it is well known that the altitude of a right triangle is the geometric mean of the two parts of the hypotenuse.

See, for example,

http://jwilson.coe.uga.edu/emt668/emat6680.folders/brooks/6690stuff/righttriangle/rightday3.html
Answered by rhidicde
ohhh... so how would I use that information to help me get to the answer?
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