Question

A baker bakes a batch of muffins and splits the batch evenly onto six different trays. She then adds five croissants to each tray. If each tray now contains at least twenty baked goods, what is the least possible number of muffins in the baker's original batch?

I don't even know where to start, if you could help me, I would really appreciate it.

Answer 1

If each tray originally had n muffins
n + 5 >= 20
n >= 15

so, there were originally 6n >= 90 muffins

Answer 2

wtf did u just say?

Answer 3

m= muffins in original batch
So, each tray has m/6 muffins and 5 croissants, which totals m/6+5. The value must be at least 20, so we have this inequality:
m/6+5 is greater than or equal to 20. We multiple each side by 6 and get:
m is greater than or equal to 90 muffins.
ANSWER: Original batch had 90 muffins