Asked by Stacie
A fullback preparing to carry the football starts from rest and accelerates straight ahead. He is handed the ball just before he reaches the line of scrimmage. Assume that the fullback accelerates uniformly (even during the handoff), reaching the line with a velocity of 7.96 m/s. If he takes 1.18 s to reach the line, how far behind it did he start?
Can I assume that acceleration is 0? If yes then I can use the x=v=Vi*t + 1/2at^2 equation. If not, I have no idea where to start.
Can I assume that acceleration is 0? If yes then I can use the x=v=Vi*t + 1/2at^2 equation. If not, I have no idea where to start.
Answers
Answered by
Damon
NO!!!!
You assume that the acceleration, a, is CONSTANT.
v = 0 + a t
at t = 1.18 s
v = 7.96 m/s
so
7.96 = a (1.18)
a = 7.96/1.18
NOW
use x = 0 + 0 + (1/2) a t^2
You assume that the acceleration, a, is CONSTANT.
v = 0 + a t
at t = 1.18 s
v = 7.96 m/s
so
7.96 = a (1.18)
a = 7.96/1.18
NOW
use x = 0 + 0 + (1/2) a t^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.