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well, consider that
4b^3+5b-3 = (2b-1)(2b^2+b+3)
(the rectangle:)
A = (4b^3 + 5b - 3) in.^2
Width = (2b - 1) in.
Pls help!? Thx
4b^3+5b-3 = (2b-1)(2b^2+b+3)
From the given information, we can determine that the width of the rectangle is (2b - 1) inches.
The formula for the area of a rectangle is length multiplied by width. So, we can set up an equation using the area formula:
A = length * width
Substituting the given values into the equation:
(4b^3 + 5b - 3) = length * (2b - 1)
To solve for the length, we need to isolate it on one side of the equation. To do this, we can divide both sides of the equation by (2b - 1):
(4b^3 + 5b - 3) / (2b - 1) = length
This gives us the length of the rectangle in terms of 'b'.