Asked by SkatingDJ
The width and area of a rectangle are shown in the figure at the right. What is the length of the rectangle?
(the rectangle:)
A = (4b^3 + 5b - 3) in.^2
Width = (2b - 1) in.
Pls help!? Thx
(the rectangle:)
A = (4b^3 + 5b - 3) in.^2
Width = (2b - 1) in.
Pls help!? Thx
Answers
Answered by
Steve
well, consider that
4b^3+5b-3 = (2b-1)(2b^2+b+3)
4b^3+5b-3 = (2b-1)(2b^2+b+3)
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