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A 100 g piece of ice (solid water) at 0 °C melted to liquid water at 75.5 °C. If all the heat came from propane (C3H8) combustion, how many grams of propane Molar mass is 44.1'

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Heatpropane=heatin water
massP*Heatcombusion=Hf*100g+100(cwater)(75.5-0)

so figure the mass.

when looking up the heat of combustion for propane, you want it in Joules/gram, if the table is in juouls/mole, you will have to convert.
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