Question
A 100 g piece of ice (solid water) at 0 °C melted to liquid water at 75.5 °C. If all the heat came from propane (C3H8) combustion, how many grams of propane Molar mass is 44.1'
Answers
bobpursley
Heatpropane=heatin water
massP*Heatcombusion=Hf*100g+100(cwater)(75.5-0)
so figure the mass.
when looking up the heat of combustion for propane, you want it in Joules/gram, if the table is in juouls/mole, you will have to convert.
massP*Heatcombusion=Hf*100g+100(cwater)(75.5-0)
so figure the mass.
when looking up the heat of combustion for propane, you want it in Joules/gram, if the table is in juouls/mole, you will have to convert.