Asked by THATONEGUY
a student puts 1.25 kg of ice in an ice cream maker with 350 g of rock salt. All the ice eventually becomes liquid water as the rock salt dissolves. Solve for the molality of the solution, then for its new freezing temperature.
Answers
Answered by
DrBob222
delta T = i*Kf*m
We need i, Kf, m.
i = 2 for NaCl
Kf we know for water is 1.86 c/m
1.25 kg ice eventually becomes 1.25 kg water.
So we need m. m = mols/kg solvent. We have kg solvent so we need mols.
mols NaCl = grams/molar mass. You know grams and molar mass, solve for mols NaCl. Use that to solve for m and use that to solve for delta T.
Then new freezing point is 0-delta T.
We need i, Kf, m.
i = 2 for NaCl
Kf we know for water is 1.86 c/m
1.25 kg ice eventually becomes 1.25 kg water.
So we need m. m = mols/kg solvent. We have kg solvent so we need mols.
mols NaCl = grams/molar mass. You know grams and molar mass, solve for mols NaCl. Use that to solve for m and use that to solve for delta T.
Then new freezing point is 0-delta T.
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