Asked by Kuaersh

Orlando is making a design for a logo. He begins with a square measuring 20 inches on each side. The second square has a side length of 16 inches, and the third square has a side length of 12.8 inches. Which square will be the first square with a side length of less than 8 inches?

Answers

Answered by Kuaersh
I'm thinking the sixth square..........
Answered by Reiny
looks like each side is 4/5 of its previous , so

20(4/5)^n = 8
(.8)^(n-1) = .4
using logs
(n-1) log .8 = log .4
n - 1 = 4.1
n = 5.1
so the 5th would be less than 8
and the 6th would be greater than 8

e.g.

1st --- 20
2nd -- 16
3rd -- 12.8
4th -- 10.24
5th -- 8.192
6th -- 6.5536

You were right, how did you reason it ?
Answered by ynw melly
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Answered by timtation
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Answered by ynw melly
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Answered by Lexi
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Answered by Welp
Mabey its for the best…
Answered by D3FC0N
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Answered by reply to welp
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Answer
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Answered by Bot
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Answered by Bot
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