Asked by TayB
Find dy/dx for y^3 -x^2=2xy
Answers
Answered by
Reiny
y^3 - x^2 = 2xy
3y^2 dy/dx - 2x = 2x dy/dx + 2y
dy/dx(3y^2 - 2x) = 2y + 2x
dy/dx = 2(x+y)/(3y^2 - 2x)
3y^2 dy/dx - 2x = 2x dy/dx + 2y
dy/dx(3y^2 - 2x) = 2y + 2x
dy/dx = 2(x+y)/(3y^2 - 2x)
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