Asked by Raz
(a).Time (t) 0 weeks 3 weeks 6weeks
Investment Value v(t) $10000 $2025 $6400
Using the data written down in the table in (a) derive a quadratic function (you BiQuad model), 𝑣(𝑡), relating the value of Peter’s share portfolio to elapsed time. Show all working.
Investment Value v(t) $10000 $2025 $6400
Using the data written down in the table in (a) derive a quadratic function (you BiQuad model), 𝑣(𝑡), relating the value of Peter’s share portfolio to elapsed time. Show all working.
Answers
Answered by
Steve
Not sure what BiQuad is, but if you want to fit a parabola through those three points, you have, assuming that
v(t) = at^2 + bt + c,
0a+0b+c = 10000
9a+3b+c = 2025
36a+6b+c = 6400
Somehow I suspect what you really wanted was v(3) = 1000-2025 = 7975, since most stocks don't bounce like that.
At any rate, solve for a,b,c for your model:
clearly, c=10000
Now just find a and b.
v(t) = at^2 + bt + c,
0a+0b+c = 10000
9a+3b+c = 2025
36a+6b+c = 6400
Somehow I suspect what you really wanted was v(3) = 1000-2025 = 7975, since most stocks don't bounce like that.
At any rate, solve for a,b,c for your model:
clearly, c=10000
Now just find a and b.
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