Asked by penny

What do I do with this??
3^3/3^6

A.1/27
B.1/9
C.9
D.-27
What do I do to solve this?? Thanks
Answered by Steve
3^3/3^6
=

3*3*3
-----------------
3*3*3*3*3*3

Now you can see that three 3's cancel out in top and bottom, so you are left with

1/(3*3*3) = 1/27

This shows why x^n / x^m = x^(n-m)
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