Question

you have a 0.200L of solution containing 250mM phosphate buffer, pH 6.8.

An equivalent amount of HCl/NaOH with respect to the total amount of phosphate in the buffer --> mmol of NaH2PO3 + mmol of NaH2PO4 = 50 mmoles.

What would the pH of the above buffer solution be after you add the following with respect to the total amount of phosphate in the buffer:

1) 1/8 equivalent amount of NaOH
2) 1/8 equivalent amount of HCl


Please explain. I'm not really looking for an answer but how it works.
Thank you

Answer 1

for 1) I got 7.42 after trying. I wanted to confirm if it is right to see if I got the process right?

Answer 2

I have no idea what this question means. My best suggestion is that if you understand the question that you use the same kind of process I used for that phosphate buffer I did last night.