Question
How did you get: x = 2; y = -1
for
Directions: Sove the system by addition
5x-3y=13
4x-3y=11
for this type of problem there is no shading correct. or am i wrong
5x-3y=13
4x-3y=11
If you subtract the two equations you get:
5x-3y - (4x-3y) = 13 - 11
The y's on the left hand side cancel:
5x - 4x - 3y + 3y = 13 - 11 --->
x = 2
If you insert x = 2 in either of the two original equations and soleve for y you find that y = -1.
for
Directions: Sove the system by addition
5x-3y=13
4x-3y=11
for this type of problem there is no shading correct. or am i wrong
5x-3y=13
4x-3y=11
If you subtract the two equations you get:
5x-3y - (4x-3y) = 13 - 11
The y's on the left hand side cancel:
5x - 4x - 3y + 3y = 13 - 11 --->
x = 2
If you insert x = 2 in either of the two original equations and soleve for y you find that y = -1.
Answers
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