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A researcher tagged 40 giant turtles in 2008. In 2009 , she returned and captured 50 turtles , 16 of which were tagged. In 2010...Question
2. A researcher tagged 40 giant turtles in 2008. In 2009 she returned and captured 50 turtles, 16 of which were tagged. in 2010 she returned again and captured 30 turtles 8 of which were tagged.
a: Use a proportion to estimate the turtle population for 2009
b: Use a proportion to estimate the turtle population for 2010
HELP MEE!!!!! I am stuck am 2010
a: Use a proportion to estimate the turtle population for 2009
b: Use a proportion to estimate the turtle population for 2010
HELP MEE!!!!! I am stuck am 2010
Answers
KYS
We know that there are 40 turtles tagged.
In 2009, 16/50 = 32% of the population was tagged, making the population 40/.32 = 125 (P/40 = 50/16)
In 2010, 8/30 = 26.7% of the population was tagged. So, the population is about 150 (P/40 = 30/8)
In 2009, 16/50 = 32% of the population was tagged, making the population 40/.32 = 125 (P/40 = 50/16)
In 2010, 8/30 = 26.7% of the population was tagged. So, the population is about 150 (P/40 = 30/8)