Asked by tarekegn
Q2. An agriculture field is rectangular,with dimensions 100m by 42m.A 20m deep well of diameter 14m is dug in acorner of the field and the earth taken out is spread evenly over the remaining part of the field. Find the increase in the level of the field.
Answers
Answered by
Reiny
This is the same style of question I just answered for you in the previous post.
Just follow the same steps.
Just follow the same steps.
Answered by
Zekarias
72cm
Answered by
gondere
h:1.465m
Answered by
Anonymous
0.8m
Answered by
Yemane
76cm
Answered by
ADU
DESSIE
Answered by
afgh
Chgg
Answered by
ADU
DESSIE
Answered by
Sosi 9B
I need to check, please
Answered by
Sosi 9B
So, d/t......
Answered by
Sosi 9B
Volume Of well=22/7×7×7×20
=3,080m^3
Area Of filed =100×42= 4200m^2
The area of the remaning part of the filed=the area of field - the area of well, so. 4200m^2 - 154m^2 (22/7×7×7)=4046m^2
The volume of the riseing filed = the volume of the earth dug out
4046(h)=3080m^3
h=0.7612'm
=76cm።።።።just like yemam.
(( I do for m.c.s 9B students "good luck") )
=3,080m^3
Area Of filed =100×42= 4200m^2
The area of the remaning part of the filed=the area of field - the area of well, so. 4200m^2 - 154m^2 (22/7×7×7)=4046m^2
The volume of the riseing filed = the volume of the earth dug out
4046(h)=3080m^3
h=0.7612'm
=76cm።።።።just like yemam.
(( I do for m.c.s 9B students "good luck") )
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