Asked by nickel
When 0.752 g of Ca metal is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 12.2C is observed.
Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC.
(Note: Pay attention to significant figures. Do not round until the final answer.)
The molar heat of reaction, H rxn, for the reaction of
Ca(s) + 2H+(aq) Ca2+(aq) + H2(g)
? is kJ/mol.
q = massH2O*sp.h.*delta T
mass H2O is 200 grams (200 mL and density is 1.00 g/mL).
specific heat H2O is 4.184 from the problem.
delta T is 12.2<sup>o</sup> C from the problem.
This is the q obtained by reacting 0.725 g Ca. Convert to a mol Ca (about 40 g but look up the atomic mass Ca on the periodic table). That will be the Joules of heat/ mol for the reaction.
Post your work if you get stuck.
fv
Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC.
(Note: Pay attention to significant figures. Do not round until the final answer.)
The molar heat of reaction, H rxn, for the reaction of
Ca(s) + 2H+(aq) Ca2+(aq) + H2(g)
? is kJ/mol.
q = massH2O*sp.h.*delta T
mass H2O is 200 grams (200 mL and density is 1.00 g/mL).
specific heat H2O is 4.184 from the problem.
delta T is 12.2<sup>o</sup> C from the problem.
This is the q obtained by reacting 0.725 g Ca. Convert to a mol Ca (about 40 g but look up the atomic mass Ca on the periodic table). That will be the Joules of heat/ mol for the reaction.
Post your work if you get stuck.
fv
Answers
Answered by
Anonymous
how would you calculate the density of an object with the mass 7kg and a volume of 2.5L
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.