When 0.752 g of Ca metal is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 12.2C is observed.
Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC.
(Note: Pay attention to significant figures. Do not round until the final answer.)
The molar heat of reaction, H rxn, for the reaction of
Ca(s) + 2H+(aq) Ca2+(aq) + H2(g)
? is kJ/mol.
q = massH2O*sp.h.*delta T
mass H2O is 200 grams (200 mL and density is 1.00 g/mL).
specific heat H2O is 4.184 from the problem.
delta T is 12.2o C from the problem.
This is the q obtained by reacting 0.725 g Ca. Convert to a mol Ca (about 40 g but look up the atomic mass Ca on the periodic table). That will be the Joules of heat/ mol for the reaction.
Post your work if you get stuck.
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