Asked by nick
N2H4(g) + H2(g) 2 NH3(g) H1 = –1876 kJ
3 H2(g) + N2(g) 2 NH3(g) H2 = –922 kJ
The H f for the formation of hydrazine: 2 H2(g) + N2(g) N2H4(g) will be ? kJ/mol.
Turn equation 1 around and change the sign of H1.
Add to equation 2, cancel like molecules appearing on both sides, and add the two delta Hs. H1(with sign changed) + H2 = H<sub>f</sub>
thank you
3 H2(g) + N2(g) 2 NH3(g) H2 = –922 kJ
The H f for the formation of hydrazine: 2 H2(g) + N2(g) N2H4(g) will be ? kJ/mol.
Turn equation 1 around and change the sign of H1.
Add to equation 2, cancel like molecules appearing on both sides, and add the two delta Hs. H1(with sign changed) + H2 = H<sub>f</sub>
thank you
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